Cant convert complex to float on python 3

Cant convert complex to float on python 3

the problem is just that your format string is for `floats` and not for complex numbers. something like this will work:

``````print({:#.3} .format(5.1234 + 4.123455j))
# (5.12+4.12j)
``````

or – more explicit:

``````print({0.real:.3f} + {0.imag:.3f}i.format(5.123456789 + 4.1234556547643j))
# 5.123 + 4.123i
``````

you may want to have a look at the format specification mini language.

`#` as format specifier will not work with the old-style `%` formatting…

then there are more issues with your code:

``````if((D== -D)|(A==0)):
``````

why not `if D==0:`? and for that it might be better to use `cmath.isclose`.

then: `|` is a bit-wise operator the way you use it; you may want to replace it with `or`.

your `if` statement could look like this:

``````if D == 0 or A == 0:
# or maybe
# if D.isclose(0) or A.isclose():
``````

The problem with using `sqrt` imported from `cmath` is that it outputs a `complex` number, which cannot be converted to `float`. If you are calculating a `sqrt` from positive number, use `math` library (see below).

``````>>> from cmath import sqrt
>>> sqrt(2)
(1.4142135623730951+0j)
>>> from math import sqrt
>>> sqrt(2)
1.4142135623730951
``````