django – How do I convert datetime.timedelta to minutes, hours in Python?

django – How do I convert datetime.timedelta to minutes, hours in Python?

Theres no built-in formatter for timedelta objects, but its pretty easy to do it yourself:

days, seconds = duration.days, duration.seconds
hours = days * 24 + seconds // 3600
minutes = (seconds % 3600) // 60
seconds = seconds % 60

Or, equivalently, if youre in Python 2.7+ or 3.2+:

seconds = duration.total_seconds()
hours = seconds // 3600
minutes = (seconds % 3600) // 60
seconds = seconds % 60

Now you can print it however you want:

{} minutes, {} hours.format(minutes, hours)

For example:

def convert_timedelta(duration):
    days, seconds = duration.days, duration.seconds
    hours = days * 24 + seconds // 3600
    minutes = (seconds % 3600) // 60
    seconds = (seconds % 60)
    return hours, minutes, seconds
td = datetime.timedelta(2, 7743, 12345)
hours, minutes, seconds = convert_timedelta(td)
print {} minutes, {} hours.format(minutes, hours)

This will print:

9 minutes, 50 hours

If you want to get 10 minutes, 1 hour instead of 10 minutes, 1 hours, you need to do that manually too:

print {} minute{}, {} hour{}.format(minutes, s if minutes != 1 else ,
                                      hours, s if minutes != 1 else )

Or you may want to write an english_plural function to do the s bits for you, instead of repeating yourself.

From your comments, it sounds like you actually want to keep the days separate. Thats even easier:

def convert_timedelta(duration):
    days, seconds = duration.days, duration.seconds
    hours = seconds // 3600
    minutes = (seconds % 3600) // 60
    seconds = (seconds % 60)
    return days, hours, minutes, seconds

If you want to convert this to a single value to store in a database, then convert that single value back to format it, do this:

def dhms_to_seconds(days, hours, minutes, seconds):
    return (((days * 24) + hours) * 60 + minutes) * 60 + seconds

def seconds_to_dhms(seconds):
    days = seconds // (3600 * 24)
    hours = (seconds // 3600) % 24
    minutes = (seconds // 60) % 60
    seconds = seconds % 60
    return days, hours, minutes, seconds

So, putting it together:

def store_timedelta_in_database(thingy, duration):
    seconds = dhms_to_seconds(*convert_timedelta(duration))
    db.execute(INSERT INTO foo (thingy, duration) VALUES (?, ?),
               thingy, seconds)
    db.commit()

def print_timedelta_from_database(thingy):
    cur = db.execute(SELECT duration FROM foo WHERE thingy = ?, thingy)
    seconds = int(cur.fetchone()[0])
    days, hours, minutes, seconds = seconds_to_dhms(seconds)
    print {} took {} minutes, {} hours, {} days.format(thingy, minutes, hours, days)

A datetime.timedelta corresponds to the difference between two dates, not a date itself. Its only expressed in terms of days, seconds, and microseconds, since larger time units like months and years dont decompose cleanly (is 30 days 1 month or 0.9677 months?).

If you want to convert a timedelta into hours and minutes, you can use the total_seconds() method to get the total number of seconds and then do some math:

x = datetime.timedelta(1, 5, 41038)  # Interval of 1 day and 5.41038 seconds
secs = x.total_seconds()
hours = int(secs / 3600)
minutes = int(secs / 60) % 60

django – How do I convert datetime.timedelta to minutes, hours in Python?

There is no need for custom helper functions if all we need is to print the string of the form [D day[s], ][H]H:MM:SS[.UUUUUU]. timedelta object supports str() operation that will do this. It works even in Python 2.6.

>>> from datetime import timedelta
>>> timedelta(seconds=90136)
datetime.timedelta(1, 3736)
>>> str(timedelta(seconds=90136))
1 day, 1:02:16