Is there a way to perform if in pythons lambda?

Is there a way to perform if in pythons lambda?

The syntax youre looking for:

lambda x: True if x % 2 == 0 else False

But you cant use print or raise in a lambda.

why dont you just define a function?

def f(x):
    if x == 2:
        print(x)
    else:
        raise ValueError

there really is no justification to use lambda in this case.

Is there a way to perform if in pythons lambda?

Probably the worst python line Ive written so far:

f = lambda x: sys.stdout.write([2n,][2*(x==2)-2])

If x == 2 you print,

if x != 2 you raise.